a] Using mirror formula,
1/u + 1/v = 1/f
1/(-11.8) + 1/v = 1/(0.5*0.542)
v = 0.265 m
= 26.5 cm answer
b] upright because magnification is positive found in third part,
c] magnification M = -v/u = -0.265/-11.8 = 0.02245
At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall...
At an Intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.568 m. (a) Locate the image of a patient 10.2 m from the mirror (Use the correct sign conventions.) cm (from the mirror) (b) Indicate whether the image is upright or inverted, upright inverted (c) Determine the magnification of the image.
At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.506 m. Locate the image of a patient 12.0 m from the mirror. (Use the correct sign conventions.) in cm Determine the magnification of the image
At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.524 m. (a) Locate the image of a patient 12.0 m from the mirror. (Use the correct sign conventions.) 0.39 Apply the mirror equation using the correct focal length and object distance to find the image distance. cm (from the mirror) (b) Indicate whether the image is upright or inverted....
At an intersection of hospital hallways, a convex mirror is mounted high on a wall to help people avoid collisions. The mirror has a radius of curvature of 0.580 m. A. Locate the image of a patient 11.9 m from the mirror. B. Determine the magnification of the image. C. Describe the image: is it upright, enlarged, virtual, real, diminished, inverted. (select all that apply)
Physics Questions A convex mirror has a focal length of magnitude 3.92 cm. (a) If the image is virtual, what is the object location for which the magnitude of the image distance is one third the magnitude of the object distance? (Enter distance in cm from the front of the mirror. If the image is real, enter NONE.) At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The...
The magnitude of the radius of curvature of a convex spherical mirror is 29.0 on. (Include the sign of the values in your answers) (a) What are the location and magnification of the image of an object placed 16 5 on in front of the mirror? location cm magnification Is this image upright or inverted? upright inverted (b) What are the location and magnification of the image of an object placed 59 5 on in front of the mirror? location...
An object is 60.1 cm in front of a convex spherical mirror that has a radius of curvature of 68.2 cm. (a) What is the image distance? cm (b) What is the magnification? (c) Is the image upright or inverted?
A convex spherical mirror has a radius of curvature of magnitude 46.0 cm. Determine the position of the virtual image and the magnification for object distances of 41.0 cm. Indicate the location of the image with the sign of your answer. Determine the position of the virtual image and the magnification for object distances of 55.0 cm. Indicate the location of the image with the sign of your answer. Are the images in parts (a) and (b) upright or inverted?
A convex spherical mirror with a radius of curvature of 100 cm generates an upright image 29.7 cm from the mirror. What is the magnification of the image?
A convex spherical mirror with a radius of curvature of 100 cm generates an upright image 29.7 cm from the mirror. What is the magnification of the image? 1.60 0.60 0.33 0.41 0 2.46