Question

Hi, I need help with this question. Please explain in details how you got the answer with steps shown for each part so I can understand it thank you.

The 2013-14 roster of the Seattle Seahawks, winners of the 2014 NFL Super Bowl, included 10 defensive linemen and 9 offensive linemen. (Data set may be found here.) The weights in pounds of the defensive linemen were 254 311 297 323 260 242 300 252 303 274 and the weights of the offensive linemen were 310 315 305 318 298 301 321 332 320 (a) Make a back to back stemplot of the weights of the offensive and defensive linemen. (Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.) Offensive lineStemsDefensive line X24 242 X25 252 X26 254 X27 260 X28 274 X | 29 | 297 x30 300 X31 303 X32 311 33 323 298 305 310 315 318 320 321 332 Find the five-number summary for the offensive line. (Enter your answers to one decimal place.) Minimum 298 Q1 Median 03 Maximum lb Ib 303.5 315 322.75 lb lb (b) Find the five-number summary for the defensive line. (Enter your answers to one decimal place.) Minimum 242 lb Median Q3 Maximum 323 256.4 285.5 306.8 lb lb

Answer 1

Sol:

use R software to get the back to back stem pot.

Install library aplpack.

create vectors defensive and offensive

use stem.leaf.backback funtion.

Rcode is:

defensive <- c(254,311,297,323,260,242,300,252,303,274);
offensive <- c(310,315,305,318,298,301,321,332,320);
library(aplpack)
require(applpack)
stem.leaf.backback(offensive,defensive,m=1)

output:

____________________________________________________
1 | 2: represents 12, leaf unit: 1
offensive defensive
__________________________
| 24 |2 1
| 25 |24 3
| 26 |0 4
| 27 |4 (1)  
| 28 |   
1 8| 29 |7 (1)  
3 51| 30 |03 4
(3) 850| 31 |1 2
3 10| 32 |3 1
1 2| 33 |   
| 34 |   
__________________________
n: 9 10   

ANSWER;

offensive		defensive
NONE	24	2
NONE	25	2 4
NONE	26	0
NONE	27	4
NONE	28	NONE
8	29	7
5 1	30	0 3
8 5 0	31	1
10	32	3
2	33	NONE
NONE	34	NONE

Solutionb:

Fivenum summary for offensive line

Rcode is

fivenum(offensive)

fivenum summary means min value,Q1,Q2,Q3,max

298 305 315 320 332

ANSWER:

MIN=298

Q1=305

Q2=median=315

Q3=320

MAX=332

Solutionc:

to get the fivenum sumamry for defensive line is

Rcode:

fivenum(defensive)

OUTPUT:

242.0 254.0 285.5 303.0 323.0

min=242

Q1=254

median=285.5

Q3=303

max=323