Question

Resources Check Answer < Question 23 of 23 > A student has 4.15 g of zinc powder, 1.00 L of a 2.50 M calcium nitrate solution, and 1.80 L of a 2.50 M lead(II) nitrate solution. Using the activity series, which of these two solutions will react with the zinc powder? O calcium nitrate O lead(II) nitrate Write the chemical reaction that occurs between the two reacting species. Include physical states. molecular equation: What volume of the solution is needed to completely react all 4.15 g of zinc powder? about us Careers oliy ter MacBook Pro

Answer 1

o Chemical Reaction between der zinc powder Calcin Nitale solution is Mitrate ③ Chemical Reaction between sine powder and lead Mitoate soleition. nt Pb (NO3)2 2n (NO)₂ + Pb zinc Reacting with load Nitrate to boom tead Crystals. This is a displacement. Reaction when a metal from the electro Chemical sedes is mined with the ions of a metal lower down for the Series, the atoms of the more Reactive metal push the is electoons on to pons of the less Reactive metal Copper inting En(s) + Cuno Cucs) +2n(ne)Cay When zinc po oder was dropped into powder was a a test tube Containing Copper Solution - The 2nc quickly began to Road with the solation producing clear foron sobatir and a darkeo -Solid at the bottom of the test tube 0 1. Calvos mot in 12 2.50M Calvo 4.15 Jan 1 molan 65.39 gan 4.15 65-39X2:50 4.15g2n Imol.in 1. Phoo 1.80L 65.39gen Imaza 2. som Ab (NO) 4.15 X 1-802 65-39X2-50 7.472 . 163.475 20.0452 0.0452 solation is required to React 97 4.15g of zinc powder L 4.15 163 475 -0.0252 0.025L solation is required to React all 4-159 of zinc powder

Molasity of Zn2+ Pons in solution after the Reaction can be Cololated by First, the number of moles of an Presad the solection is Caculated by in the formula mass of an Molar mass of 2n! Moles of an= a 4.15 g 1 65-38 g/mol = 0.0634 mol In the reaction, one mole of renc Reats with one mole of Pb(u) ritrate to. form one mole of zinc Nitrate Thosefore 0.0634 moles of zinc Nibrate Reacts with load (a) Mitrale to form 0.0634 moes of Zinc neitrate The volume of the solution is it 0.0452 inti Mass of solite Molasity - I V of solzition. = 0.0634 mol 0.045L = 1.400