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Acids & Base Worksheet 14a (Intro) Part 3: Calculations Copy the product name and pH from the table on the previous page, the
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Answer #1

Part a

For aspirin

pH = 3

we know that

pH = - log [H+]

[H+] = 10^-pH = 10^-3 M

We know that

[H+] [OH-] = 10^-14

[10^-3] [OH-] = 10^-14

[OH-] = 10^-11 M

pOH = - log [OH-]

= - log (10^-11)

= 11

Part b

pH = 8

we know that

pH = - log [H+]

[H+] = 10^-pH = 10^-8 M

We know that

[H+] [OH-] = 10^-14

[10^-8] [OH-] = 10^-14

[OH-] = 10^-6 M

pOH = - log [OH-]

= - log (10^-6)

= 6

Part c

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