Question

2 kg What is the weight of the measuring stick if it is balanced by a support force at the 1 m mark? The acceleration of gravity is 9.81 m/s2 Answer in units of N

Answer 1

mg 3.SM 1M 3

Gravitational acceleration = g = 9.81 m/s²

Weight of the measuring stick = W

Mass of the ball = m = 2 kg

The center of gravity of the measuring stick will lie at the center of the stick.

Distance of the center of gravity from the support = D₁ = 2.5 m

Distance of the ball from the support = D₂ = 1 m

Taking moment balance about the support,

WD₁ = mgD₂

W(2.5) = (2)(9.81)(1)

W = 7.848 N

Weight of the measuring stick = 7.848 N