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can you please answer this NMR
- вто 7:26 PM Sat 2 Nov кб 5 Cзн6CI2 то, - з + оо Dr. Abeer Al-romaidan C8H10 pom
7:26 PM Sat 2 Nov 81% < s TORO of 2 e too C4H100 Dr.Abeer Al-romazan C7H8
7:26 PM Sat 2 Nov 81% < s TORO of 2 e too C4H802 Dr. Aber Al-romaizan Hiw C3H602
C9H100 TTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT ووووووووووو
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Answer #1

Answer D C3H6Cl2 Degree of unsatura biom= 0 HANOR 62.2 (quintet, 2H) - CH CH CHE 3.8 ( triplet, 4413 -CH2-c1 cquivalent struc4) CHE DV=4 8 2.4 (s, 3H) T.2 (m, 5H) elo Ar Cort Structure / H T CH3_ 2.4(5) 1.7.20m) 5) C4H802 D.V-1 dinct, 34) = C1 CH2 2.Sush $1.55 ( 31, tsiplet) 11 ay did ( ?11, quartet) = cyclo 615 ( 2.11, doublet) a uŹh 7.9( 211, doublet) 10-0 ( lll, Siglet)

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