Given:
Q = 57300 J
m = 376 g
C = 0.9 J/g.oC
Ti = 24.12 oC
use:
Q = m*C*(Tf-Ti)
57300.0 = 376.0*0.9*(Tf-24.12)
Tf -24.12 = 169.33 oC
Tf = 193.45 oC
Answer: 193.45 oC
a 376 g aluminum engine part at an initial temperature of 24.12 Enter your answer in...
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