Question

Name: How moch energy (work) is expended to move an object 30 with a force of 5 Ihe? eet can an object be moved with 50 ft. lb, of energy if it takes 2.5 lbs of force? How mary wwy icht bulb will use a specifie amount of energy in 30 minutes. How many meters can you move a car with the same amount of energy if it takes 200 Newtons of force to Our Styhawks use 160 horsepower engines. If we connected the engine to a generator and assume that there is no energy loss due to friction or resistance, how many 200 watt light bulbs could we light? S. Assuming the light bulbs are 120 volts, how much current would be flowing in the above problem? The IDGs (Integrated Drive Generators) in a 767 produce 110 kiloWatts. What horsepower engine would we need to turn the IDG? 6. 7. At max output at 115 volts, how much current is being produced in problem 6? 8. How many electrons pass a given point in the output wire of IDG in problem 6 in one Our Skyhawks use a 28 volt alternator capable of producing 60 amps. How this? 10. How many horsepower does the alternator in problem 9 take from the engine at max ity? (Assuming the alternator is 100% efficienL) l I. The Skyhawk landing light draws 5 amps at 28 volts. How many watts is it? 12. Referring to 11 above, how many joules of energy does it use in 3 minutes? | 13Ί Referring to l l above, how many electrons pass through the light in 3 minutes? 14. A Skyhawk travels for 1 nautical mile (6070 ft) requires 270 Ibs of thrust to maintain altitude at a forward speed of 110 feet per second. How long would you have to burn a 60 watt light bulb to consume the same amount of energy? (Give answer in hours.) (this problem can be simple or complex depending on your approach.)

Answer 1

(a) Voltage = 28 Volt I = 600 mp Watts of this alternator (P) = VI = 28 times 60 = 1680 Watt (b) Because 1 Horse - Power = 746 Watts So = 1680/746 = 2.25 Horse - Power Voltage = 28 Volt I = 5 amp Watt = V middot I = 28 times 5 = 140 Watts Uses energy by it in 3 min t = 3 minutes = 3 times 60 = 180 sec W = (Energy) = V it = 140 times 180 Joules = 2.52 times 10^4 Joules Since 9 = it i = current = 5 times 180 = 900 cool Number of electron in 900 coulombs. n = 900/1.6 times 10^-19 = 5.62 times 10^21