Question

A pressure versus volume (P-V) diagram for a system is shown in the figure. The arrows of the curve indicate the direction of the process, and the points of interest are labeled. The values for the points in the diagram are shown 0 in the table. Volume (m2) Pressure (Pa) Po = 1.37 x 10 Vo 26.6 Pi 1.37 x 104 И 3 =21.7 2=16.2 P2 5.97 x 103 V 13.3 Ps 5.97 x 10 V4=13.3 P4 3.20 x 103 Ps= 1.00 x 10 Vs 9.21 Calculate the amount of work done on the system from 0-2 (Wo) and then for the entire curve from 0-5 (Was). Volume (m) Wo2 J Wos = Pressure (Pa)

Answer 1

Work done on system from 0-2 1.37XL04 5.99x180) A A work done on system (0-2) Arer between PV curve & Volume axis is ta ģ Tuem?) Trapiztum Rectangle 16.2 m2 21.7m3 26.6 m3 = 1100.597010" ++3710) (21.7 -16.2) +(1.37x10 (266-21-7) -1(1.967 X1%) 5.5 + 1.37x4.9 x104 = 5.400104 + 6:21x10" = 12.11x104 Joule = 121.1810 on system from 5121K Joule work done 2 . 13.7410 = 1.378104 13.71 fal work done AIAL At Ay s.97 pst- & 3.2012 (Ares beth curre e volume ax's) PAIL 9.21 7 16: 2 017 , V 26.6 8.5xlo Jone Rectorgle- Irapizian a A (3:2x10 + 1*210) 6355 ReeAz = (5.97X103) (16.2-13-3) = 17.3x10 3 Joule Trap Az = 1 (8374103 5.97X10²) (21.7 -16-2) = 54.0 x103 Joule Au= (137x103) (26-6-21.7) = 67.1 x103 Toute = 146.9 8103 u 147k Joule work done = 8.5x10 - 8.5xlosti. 3xlost su oxlot 67.1800-