Question

2) You may do this problem by hand or in R. It is recornmended you use R to gain more familiarity with it. The following table summarizes some statistics for r 4 groups. Yi 1 10 10.69 0.830 2 12 12.17 0.894 3 8 11.95 0.510 4 9 11.82 0.741 ni Use it to complete the ANOVA table. df SS MS F p-value Treatment -- .. “ -- Error Total
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Answer #1

r=4 is the number of groups

The total number of observations is

rl rl

the grand mean is

ar{ar{Y}}=rac{sum_{i=1}^rn_iar{Y}_i}{n}
The degrees of freedom for Treatment

df_{ ext{treat}}=r-1

The sum of square Treatment is

i= 1

Mean square of treatment is

SSTR treat

The degrees of freedom for error

errorn_

The sum of square Error is

τ ni

Mean square of Error is

MSE SSb dferror

Total Degrees of freedom

total n-1

Sum of square total is

SST SSTR + SSE

F statistics is

F=rac{ ext{MSTR}}{ ext{MSE}}

p-value is

ext{p-value}=P(F> ext{Fstat})

R code for all these (all statements starting with # are comments)

#set the number of groups
r<-4;
#set the sample size for each group
n<-c(10,12,8,9)
#set the sample mean
ybar<-c(10.69,12.17,11.95,11.82)
#set the sample variances
s2<-c(0.830,0.894,0.510,0.741)
#calculate the total number of observations
nT<-sum(n)
#calculate the grand mean
ybarbar<-sum(n*ybar)/nT

#Treatment
#degrees of freedom
dftr<-r-1
#sum of square treatment
sstr<-sum(n*(ybar-ybarbar)^2)
#mean square treatment
mstr<-sstr/dftr

#Error
#degrees of freedom
dfe<-nT-r
#sum of square Error
sse<-sum((n-1)*s2)
#mean square error
mse<-sse/dfe

#df total
dftot<-nT-1
#sum of square total
sst<-sse+sstr

#F statistics
f<-mstr/mse

#p-value, P(F>f)
pvalue<-pf(f,dftr,dfe,lower.tail=FALSE)

#print the ANOVA values
sprintf("Treatment: df=%d, SS=%.4f, MS=%.4f, F=%.4f, p-value=%.4f",dftr,round(sstr,4),round(mstr,4),round(f,4),round(pvalue,4))
sprintf("Error: df=%d, SS=%.4f, MS=%.4f",dfe,round(sse,4),round(mse,4))
sprintf("Total: df=%d, SS=%.4f",dftot,round(sst,4))

##get this output

> #print the ANOVA values > sprintf (Treatment : dfe%d, SS 8.4, Ms % . 4f, F % . 4f, p-value-8.4f,dftr, [1] Treatment : df-3 , ss-13.4326, MS-4 . 4775, F 5.8471, p-value-0.0024 > sprint f ( Error: dfe%d, SS % . 4, MS % . 4f,dfe, round (33e, 4) , round (mse, 4)) [1] Error: df-35, SS=26.8020, MS=0.7658 > sprintf (Total: df %a, ss % . 4f,dftot,round (33t,4)) [1] Total : df=38, SS=40.2346

Make this ANOVA table

Source df SS MS F p-values
Treatment 3 13.3426 4.4775 5.8471 0.0024
Error 35 26.802 0.7658
Total 38 40.2346
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