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Incorrect. Before working this problem, review Conceptual Example 14. A pellet gun is fired straight downward from the edge of a cliff that is 14.0 m above the ground. The pellet strikes the ground with a speed of 28.5 m/s. How far above the cliff edge would the pellet have gone had the gun been fired straight upward? Number [22.19 Units
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Answer #1

Given is:-

Height of the cliff  h = 14m

Speed of pellet when it reaches the ground  v -28.5m/s

Now,

Using third equation of motion

v^2 = u^2 + 2as

by plugging all the vales we get

(23.5)2-u2 + 2(9.8) (14)

which gives us the initial speed of the pellet, which is

u-23.2m/s

Now again using the third equation of motion but this time in upward direction, hence g=-9.8 m/s2

thus

(0)(23.2) 2(-9.8)(s (Because at maximum height the upward velocity will be zero)

which gives us

s = 27.46m

This is the height the pellet gone above the cliff

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