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Question 6 Not answered Marked out of 1.00 If the above reaction could be done at 3399 K, what would be your estimate for AGº
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Question 5 Correct Mark 1.00 out of 1.00 Use AG° =AH° -TASⓇ to calculate AG (in kJ) at 298 K for : 2002(g) +4H20(1) ► 2CH3OH(
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Answer #1

Ans 8

2POCl3 = 2PCl3 + O2

Enthalpy change for the reaction = sum of Enthalpy of formation of products - sum of Enthalpy of formation of reactants

Hrxn° = 2*Hf°(PCl3) + Hf°(O2) - 2*Hf°(POCl3)

Hrxn° = 2*(-287) + 0 - 2*(-592.7) = 611.4 kJ

Entropy change for the reaction = sum of Entropy of formation of products - sum of Entropy of formation of reactants

S° = 2*Sf°(PCl3) + Sf°(O2) - 2*Sf°(POCl3)

S° = 2*(311.7) + 205 - 2*(324.6)

= 179.2 J/K x 1kJ/1000 J

= 0.1792 kJ/K

Temperature T = 2268 K

Grxn° = Hrxn° - TS°

= 611.4 kJ - 2268K x 0.1792 kJ/K

= 204.97 kJ

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