1) Apply the definition of self inductance to determine an expression {N, D, A} for the...
2) Apply the definition of self inductance to determine an expression (N, W, a, b, for the self inductance, L. of a toroid having N loops, width W inner radius a and outer radius b. The toroid has a circular shape but each loop of the toroid has a rectangular shape with area = (W)(b-a). The interior of the toroid is filled with material having permeability H.
on a Self- and mutual - inductance coefficients of long solenoids. this is a very simple problem single long solenoid and two concentric long solenoids. Consider a long solenoid with n = 100 loops per deci- I meter of lenght °(1 decimeter Cem )=104m) and loop ross-section S= 100 cm 1) Calculate the self-inductance I per urut lenght of the solenoid. 2) Consider to insert a second long solenoid inside the first solenoid and coaxial with it Caf. rig. HA...
question 6 please 5. ucta Using the results of the previous problem (7.4), derive the following self - inductance parameters; a) The magnetic flux density B inside the solenoid of length h and magnetic material u on the interior b) The total flux Φ tot-J B-dS on the interior loop of a solenoid c) The flux linkage linking all of the loops of the structure d) The self-inductance L of the solenoid e) Now for a fine magnet wire (copper...
Find the cross-sectional area of a 5.4 cm long solenoid with 520 turns and a self-inductance of 43 µH.
Find the cross-sectional area of a 5.6 cm long solenoid with 525 turns and a self-inductance of 42 µH.
on a 1311 HA5.4 Self- and mutual - inductance 10 coefficients of long solenoids. [40 points) this is a very simple problem single long solenoid and two concentric long solenoids. Consider a long solenoid with n= 100 loops per deci- meter of lenght °C 1 decimeter (dm) = 10^m') and loop ross-section S=100 cm? 1) Calculate the self-inductance I per urnit lenght of the solenoid. [20 points) > 22 Consider to insert a second long solenoid inside the first solenoid...
Find the cross-sectional area of a 5.0 cm long solenoid with 500 turns and a self-inductance of 40 pJ-I. Please explain the process to get the answer.
Suppose you wish to make a solenoid whose self-inductance is 1.2 mH. The inductor is to have a cross-sectional area of 2.00 10-3 m2 and a length of 0.053 m. How many turns of wire are needed?
Suppose you wish to make a solenoid whose self-inductance is 1.4 mH. The inductor is to have a cross-sectional area of 1.7 x 10-3 m2 and a length of 0.059 m. How many turns of wire are needed?
Suppose you wish to make a solenoid whose self-inductance is 2.1 mH. The inductor is to have a cross-sectional area of 1.6 x 10-3 m2 and a length of 0.070 m. How many turns of wire are needed?