Question

2. Calculate the number of moles of hydrogen gas generated if the cudiometer volume is 76.34 mL, the total pressure of H, generated over water is measured to be 755.0 torr, and the temperature is 22.0°C. (Pxo ar 22.0°C - 19.8 torr) (R = 62.36 L-torr/mol Kor 0.08206 L atm/mol K) 3. What is the percent yield of hydrogen gas if your answer from question 2 is the actual yield and your answer from question 1 is the theoretical yield?

Answer 1

2.

total pressure   = 755 torr

PH2O                = 19.8 torr

PH2   = total pressure - PH2O

          = 755-19.8

            = 735.2 torr

PH2   = 735.2/760   = 0.9674 atm

V   = 76.34ml   = 0.07634L

T = 22+273   = 295K

R = 0.08206L-atm/mole-K

PV = nRT

n    = PV/RT

        = 0.9674*0.07634/(0.0821*295)

         = 0.00305moles

The no of moles of H2 = 0.00305moles

mass of H2 = 0.00305*2   = 0.0061g

3.

percent yield   = actual yield*100/theoretical yield

                         = 0.0061*100/

please give question 1