2.
total pressure = 755 torr
PH2O = 19.8 torr
PH2 = total pressure - PH2O
= 755-19.8
= 735.2 torr
PH2 = 735.2/760 = 0.9674 atm
V = 76.34ml = 0.07634L
T = 22+273 = 295K
R = 0.08206L-atm/mole-K
PV = nRT
n = PV/RT
= 0.9674*0.07634/(0.0821*295)
= 0.00305moles
The no of moles of H2 = 0.00305moles
mass of H2 = 0.00305*2 = 0.0061g
3.
percent yield = actual yield*100/theoretical yield
= 0.0061*100/
please give question 1
2. Calculate the number of moles of hydrogen gas generated if the cudiometer volume is 76.34...
Gas Laws Pre-Lab Name Section 1. Calculate the number of moles of hydrogen gas generated when 0.214 g of zinc reacts with hydrochloric acid Zn(s) + 2HCl(aq) --ZnCl (aq) +Hy(@) 2. Calculate the number of moles of hydrogen gas generated if the cudiometer volume is 76.34 mL, the total pressure of H, generated over water is measured to be 755.0 torr, and the temperature is 22.0°C. P o ar 22.0°C = 19.8 torr) (R = 62.36 L torr/mol K or...
Gas Laws Pre-Lab Name Section 1. Calculate the number of moles of hydrogen gas generated when 0.214 g of zinc reacts with hydrochloric acid. Zn(s) + 2HCl(aq) --ZnCl(aq) +H.(8) 2. Calculate the number of moles of hydrogen gas generated if the cudiometer volume is 76.34 mL, the total pressure of H, generated over water is measured to be 755.0 torr, and the temperature is 22.0°C. (Psoat 22.0°C - 19.8 tort) (R = 62.36 L tor/mol K or 0.08206 L atm/mol...
Taking into account the vapor pressure of water, how many moles of hydrogen gas, n, are present in 343 mL at 752 torr and 29 ∘C?The value of the gas constant R is 0.08206 L⋅atm/(mol⋅K). You may also find the conversion factors 1 atm=760 torr and TK=TC+273 useful. Express the number of moles to three significant figures.
Part C Taking into account the vapor pressure of water, how many moles of hydrogen gas, n, are present in 311 mL at 752 torr and 29 °C?The value of the gas constant Ris 0.08206 L-atm/(mol-K). You may also find the conversion factors 1 atm = 760 torr and Tk = Te + 273 useful. Express the number of moles to three significant figures. View Available Hint(s) 190 AED ? mol Submit
Experiment 12. Generating Hydrogen Cas A. Percent yield of hydrogen gas Mass of magnesium -0.051 Volume of gas (actual) Temperature of H gas Atmospheric pressure (see barometer) 20 °C 24 mmHg 26PmHg mmHg Vapor pressure of water there mmtig Partial pressure of He gas Calculate the moles of hydrogen gas that should have been produced, starting with the mass of Mg and using the balanced equation. Mg (8) + 2 HCI (aq) → MgCl(aq) + H2 (8) 0.08ling Imoling ....
How many moles of gas are in a container that has a volume of 20.5 mL, temperature of 303 K, and pressure of 1.10 atm? Assume ideal gas behavior. L atm L kPa • Use R-0.08206 mol K vor 8.314 v for the ideal gas constant. mol K • Your answer should have three significant figures.
Need help solving these last 7 questions. Please use the data above to calculate the answers. Molar Volume of a Gas Room temperature (T2): Barometric pressure: C be & torr Tria .0544 Data Trial 2 Trial 1 Mass of Mg strip Temperature of water in the 600-mL beaker 8.1 torr 142 Vapor pressure of water at the temperature in the 600-mL beaker torr torr S6.4 A.1 Volume of gas collected at room temperature mL mL ,67as 0541 S04L Volume of...
Consider the following gas reaction at STP: H2(g) +O2(g) -->H2O2(g). Calculate the final volume if 2.0 moles of hydrogen gas react with 2.0 moles of oxygen gas. (R=0.08206 L*atm/mol*K)
The van der Waals equation gives a relationship between the pressure p (atm), volume V(L), and temperature T(K) for a real gas: .2 where n is the number of moles, R 0.08206(L atm)(mol K) is the gas con- stant, and a (L- atm/mol-) and b (L/mol) are material constants. Determine the volume of 1.5 mol of nitrogen (a .39 L2 atm/mol2. b = 0.03913 L/mol) at temperature of 350 K and pressure of 70 atm. The van der Waals equation...
In the first cell, 42.51 mL of hydrogen gas were formed at the cathode.The temperature was 21.5C and the vapor pressure of water at this temperature is 19.240 torr. The Barometric pressure was 758.8 mm Hg and the height of water in the buret above the level of water in the beaker was 8.2 cm. Calculate: a. Partial Pressure of Hydrogen (H2) in buret (PH2 = Barometric – VP – Pheight) (The pressure due to the height of water still...