When 1.3 g of KClO3 was added to 151.1 g of water in a calorimeter, the temperature dropped by 0.588 °C. The heat capacity of H2O is 4.184 J/g°C. Assume the specific heat of the solution equals that of pure H2O and that the calorimeter neither absorbs nor leaks heat. What is the molar heat of solution of solid potassium chlorate? Give the answer in kJ.
mass of KClO3 = 1.3 g
moles of KClO3 = 1.30 / 122.55 = 0.0106 mol
mass of solution = 151.1 + 1.3 = 152.4 g
temperature dropped = 0.588 oC
Cp = 4.184 J / g oC
Q = m Cp dT
= 152.4 x 4.184 x - 0.588
Q = -375 J
delta H = - Q / n
= 0.375 / 0.0106
delta H = 35.37 kJ/mol
molar heat of solution = 35.4 kJ
When 1.3 g of KClO3 was added to 151.1 g of water in a calorimeter, the temperature...
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