According to HOMEWORKLIB RULES we have to answer only first one problem
pH = pKa + log(NaNO2/HNO2)
Ka for HNO2 = 4x10^-4
pKa = 3.4 (-logKa = pKa)
3.55 = 3.4 + log(A-/HA)
log(A-/HA)= 0.15
A-/HA = (10^0.15 = 1.41)
A-/HA = 1.41
A- = 1.41 HA
A- + HA = 1
1.41 HA + HA = 1
2.41 HA = 1
HA= 0.414
HNO2 = HA = 0.415 L
NaNO2 = A- = 0.585 L
CROSS CHECK
pH = pKa + log(NaNO2/HNO2)
= 3.4 + log 0.585/0.415
= 3.4 +0.149
= 3.549
=3.55
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