5) Balance the following by the method of reactions: a. SO32- + MnO4 + H+ +...
5) Balance the following by the method of % reactions: a. SO32- + MnO4 + H+ + SO42- + Mn2+ + H2O
Balance each of the following redox reactions occurring in acidic solution. A. SO32−(aq)+MnO4−(aq)→SO42−(aq)+Mn2+(aq) Express your answer as a chemical equation. Identify all of the phases in your answer. B. S2O32−(aq)+Cl2(g)→SO42−(aq)+Cl−(aq) Express your answer as a chemical equation. Identify all of the phases in your answer.
References] Balance each of the following oxidation-reduction reactions by using the oxidation states method. (Use the lowest possible coefficients for all reactions.) Cl2(g)+Ga(s)- Ga3 (aq) CI (aq) a. Ga3 (aq)+ CI (aq) Cl2(9) + Ga(s) O2(9)+ H2O(1)+Sn(s)Sn(OH)2(s) b. H2O (1) + O2(9) + Sn(OH)2 (s) Sn(s) H* (aq)MnO4(aq) +Cr2 (aq ) -Mn2 (aq) +Cr3+ (aq) +H2O(l) с. Cr (aq) H (aq) + MnO4 (aq) + Cr (aq) + Mn2+ (aq) + Н. О(1) 6 item attempts remaining Submit Answer Try...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) MnO4-(aq) + Cl-(aq) Mn2+(aq) + Cl2(aq) MnO4- + Cl- + H+ + H2O Mn2+ + Cl2 + H+ + H2O (b) Cr2O72-(aq) + NO2-(aq) Cr3+(aq) + NO3-(aq) Cr2O72- + NO2- + H+ + H2O Cr3+ + NO3- + H+ + H2O (c) Tl2O3(s) + NH2OH(aq) TlOH(s) + N2(g) Tl2O3 + NH2OH + OH- + H2O TlOH(s) + N2 + OH- + H2O (d) CrO42-(aq) + C2O42-(aq) Cr(OH)3(s) + CO2(g) CrO42- + C2O42- + OH- + H2O Cr(OH)3 + CO2 + OH- + H2O
After balancing the following redox reaction, what is the coefficient of H+? MnO4-(aq) + SO2(g) + H2O(l) → Mn2+(aq) + SO42-(aq) + H+ (aq)
How do I solve the following redox reactions? What are the balanced half-reactions? What is the final balanced equation? Problems 1. MnO4 (aq) + SO32- (aq) → MnO2 (s) + SO42- (aq) in basic solution 2. NO2" (aq) + Al(s) NH3(aq) + Al(OH)4 (aq) in basic solution 3. Mn2+ (aq) + NaBiO3 (s) → Bi* (aq) + MnO4 (aq) + Nat (aq) in acidic solution 4. As2O3 (s) + NO3- (aq) → H3ASO4 (aq) + N2O3 (aq) in acidic solution...
1. Balance the following redox reaction using the method of half-reactions (also called the ion-electron method). Mn2+ (aq) + NaBiO3 (s) → Bi3+ (aq) + MnO4- (aq) + Na+ (aq) 2. Balance the following reaction is basic media. (remember you should have no H+ ions in your final reaction.) Pb(OH)42- (aq) + ClO- (aq) → PbO2 (s) + Cl- (aq)
Complete and balance the following reactions: H2O2 + MnO4- ----> O2 + Mn2+ (acid solution) H2O2 + MnO4- ----> O2 + Mn2+ (base solution) * please clearly explain
5. Balance the following reaction that occurs in base, using the half-reaction method. NO(g) + MnO4-1(aq) ---> NO3-1(aq) + MnO2(s) When this reaction is balanced, there will be (A) OH-1(aq) and (B) H2O(l) in the final balanced equation. (Enter numbers without the plus sign.) 6. 0.122 grams of an unknown triprotic acid was neutralized with 37.2 mL of a 0.125 M NaOH solution. What is the Molar Mass of the unknown acid? Report the answer to three sig figs and...
Balance the following redox reactions by balancing the half reactions and then combine the half reactions to get the overall balanced redox reaction with the lowest possible whole number coefficients. 1. Consider the following unbalanced redox reaction: MnO2(s) + BrO3−(aq) → MnO4−(aq) + Br−(aq) (a) Balance the corresponding half reactions in acidic conditions using the lowest possible whole number coefficients. (Enter coefficients for one and zero. Blanks will be marked incorrect.) MnO2(s) + H2O(l) + OH−(aq) + H+(aq) + e− → MnO4−(aq) + H2O(l) + OH−(aq) + H+(aq)...