(a)
R code:
x=rnorm(100,0,1)
p=length(subset(x,x<1.645))/100
p
pnorm(1.645)
(b)
R code:
x=matrix(0,800,1000)
p=1:800*0
for(i in 1:800)
{
x[i,]=rnorm(1000,0,1)
p[i]=length(subset(x[i,],x[i,]<1.645))/1000
}
mean(p)
var(p)
Output:
> mean(p)
[1] 0.9499062
> var(p)
[1] 4.545178e-05
Yes mean(p) is very closed to 0.95.
For expert using R , I appreciate everything can be helpful.. Thank you
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