175Q16
Because the number of moles of gas are increasing from 6 to 7 in the reaction shown below, at constant pressure ΔE is predicted to be slightly ________ negative than ΔH.
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
Δn = total no of moles of products - total no of moles of reactants in gases
= (3 + 4) - (1 + 5) = 1
ΔH = ΔE + ΔnRT
ΔH = ΔE + 1RT
ΔE = ΔH -RT
at constant pressure ΔE is predicted to be slightly RT negative than ΔH.
175Q16 Because the number of moles of gas are increasing from 6 to 7 in the...
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un plase uansion from a liquid to a gas • an increase in the number of moles of a gas during a chemical reaction EXAMPLE 17.1 Predicting the Sign of Entropy Change Predict the sign of AS for each process: (a) H2O(g) → H2O(1) (b) Solid carbon dioxide sublimes. (c) 2 N2O(g) —> 2 N2(8) + O2(g) SOLUTION (a) Since a gas has a greater entropy than a liquid, the entropy decreases and AS is negative. (b) Since a solid...
When .514 g of C12H10 undergoes combustion in a bomb calorimeter, the temperature increases from 25.8oC to 29.4oC. The heat capacity of the bomb and all of its contents is 5.86 kJ/oC. What is the heat released per mole of C12H10? Is the number you calculated ΔE or ΔH? Why? Is ΔE = ΔH for this reaction? Why? Balanced reaction: 2 C12H10 (s) + 29 O2 (g) → 24 CO2 (g) + 10 H2O (g) If ΔE and ΔH are...