3. Initial angular speed, wo = v/r = 29.8/0.330 = 90.3 rad/s
Angular acceleration, = a/r = -(1.60/0.330) = - 4.85 rad/s2s2
Final angular speed, w = 0
(a) Using, w2 - wo2 = 2, we have,
02 - 90.32 = -2*4.85* => = 840.63
So, number of revolution = (840.63/2*3.14) = 133.86 rev
(b) When car travels half the distance, angular displacement will be, ' = (840.63/2) rad = 420.32 rad
Again using the same equation as above, we have,
w2 - 90.32 = -(2*4.85*420.32) = -4077.104
=> w2 = 4076.986 => w = 63.85
Thus, angular speed = 63.85 rad/s
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