Question

0 A particle moves In the zy plane with constant a velocity vector at time t 0 s is e-8.00m/eェ-7,50m sy. Find the magnitude of the velocity vector at time t-4.30 s. At time t = O s, the position vector for the particle is r 7.20m Z + 8.40my. The acceleration is given by the vector ā 8.40m/82z + 8.00 n/-, The Tries 0/6 Part B What is the angle between the velocity vector and the positive x-axis at time t 4.30 s? Tries 0/6 What is the m ude of the position vector at time t 4.30 s? Part D Tries 1/6 Previous Tries

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