Homework Answers
Answer:
Step 1: Explanation
Kp is the equilibrium constant calculated from the partial pressures of a reaction equation. It is used to express the relationship between product pressures and reactant pressures
Step 2: Write the balanced the chemical equation
2SO2 (g) + O2(g) <--------------> 2SO3(g)
Given, PSO2 =0.001915 atm , PO2 = 0.001111 atm , PSO3 = 0.0166 atm
Step 3: Calculation of KP
2SO2 (g) + O2(g) <--------------> 2SO3(g)
we know, The Kp expression can be written as
Kp = P2SO3 / ( P2SO2 × PO2 )
on substituting the values of partial pressure
=> Kp = ( 0.0166 )2 / ( (0.001915 )2 × 0.001111 ) = 6.76 × 104 [ exact value = 6.763392017 × 104 ]
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04 Question (1 point) A reaction vessel contains an equilibrium mixture of SO2, O2, and SO3....
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A reaction vessel contains an equilibrium mixture of SO2, O2,, and SO3. The reaction proceeds such that: 2SO2 (g) + O2 (g) ----> <---- 2SO3 (g) The partial pressures at equilibrium are Pso2=0.001111 atm PO2 = 0.002728 atm PSO3 =0.0166 Calculate the Kp for the reaction.
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Question (1 point) Areaction vessel contains an equilibrium mixture of SOs, Os, and SOs The reaction proceeds such that 12/08/19 250,(9) +0,($) — 280,() 7th attempt Se Periodic Table 0 Set The partial pressures at equilibrium are: Pso, -0.002720 atm Po, = 0.001111 atm Pso, = 0.0166 atm Calculate Kp for the reaction x 10 14 OF 16 QUESTIONS COMPLETED < 05/16 > + VIEW SOLUTION Type here to search
I've been trying to solve this for the longest time and it keeps
telling me it's wrong.
05 Question (1 point) e See page 625 A reaction vessel contains an equilibrium mixture of SO2, O2, and SO3. The reaction proceeds such that: 2802(g) + O2(g) + 2503() V 6th attempt . See Periodic Table D See Hint The partial pressures at equilibrium are: Pso, = 0.001312 atm Po, = 0.001919 atm Pso, = 0.0166 atm Calculate Kp for the reaction.
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