Question

6) Clz antenah sudo "3-A Predict 116 grams methylpropane major product. 150 grams Az occurs used. Tonni stri limiting reactant? boligt bir- theoretical field? yield if 140 grams product forms? actual %

Answer 1

tuz il the macht methylpropane (Major prodent) 2-chloro-2-methye propane (X Here 116g methyl pro pane and 150 g the given moler massg methylpropane = 12x4+ + lxlo = 58g/mol - Culio Molar massa lr =351 X 2 = 7lglnol moleg Methyle pro pane = 116 = amole molugan = 150 = 2.11 mole. now for I mole og methylprope Imole he is needed lo for Imole methye propane 2 mole of Che will need need and soll moleg cl av allable. so methye propane is limiting reautant and product will formed according to this. Imole of methyle propane gives Inde X so 2 mole will give a molex Molermass of X (2-chloro-2 methye propane) massy X produced theoritical = 2x moler mass = 2x(57+35.5) =1185100g). Theoritical yield = 105.0og. But actually we got luog og produto so % yield a Actual Yield $100- 140 X 100 Thenitical yield % Yield = 76%