Homework Answers
The balanced equation is
H2SO4 + 2 KOH -----> K2SO4 + 2 H2O
Number of moles of H2SO4 = molarity * volume of solution in L
Number of moles of H2SO4 = 0.737 * 0.035 = 0.0258 mole
From the balanced equation we can say that
1 mole of H2SO4 requires 2 mole of KOH so
0.0258 mole of H2SO4 will require
= 0.0258 mole of H2SO4 *(2 mole of KOH / 1 mole of H2SO4)
= 0.0516 mole of KOH
molarity of KOH = number of moles of KOH / volume of solution in L
0.827 = 0.0516 / volume of solution in L
volume of solution in L = 0.0516 / 0.827 = 0.0624 L
1 L = 1000 mL
0.0624 L = 62.4 mL
Therefore, the volume of KOH required would be 62.4 mL
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