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4. Assume the average time calories burned per day for a particular population was 2400 with standard deviation of 300 Assume they all eat exactly 1600 worth of calories per day. A common saying is that you must burn a net of 3600 calories to lose a pound of fat (it is more complicated than that!). Another way of saying this is the difference between what they have ate and what they burned must be 3600 calories to lose one pound of fat in a day. (a) Write down the equation relation pounds of fat loss (Y), calories burned (Xi), and calories eaten (1600). Assume there are no other factors. (b) Find the average number of pounds of fat lost per day.(c) If the population survives 10 days, what is the total pounds of fat lost on average? (d) Find the variance of pounds of fat lost per day.

math   Statistics-And-Probability   
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Sol et fat loss is deyoted wit y しet Colones bwmeds denoted with nt given t nat Avevoge Caloyies burned per day Standayd deviation of calbries bun ed Cone must bum 3600 caioviesナ。Lose a Pound o4 fat Ca) -fort loss and Ca lovies borned İs in the ven cendicution yelated to poundd 04 y: 1600+3600(1) Co) The average mUM be: Of pounds of fot e mum ber of pounds or fut Cb) ose per dayoCavpate y= 1600 +3600(1) 1600七3600 (2400) =C) If he population aurives totai pound of fat lost an avevaje is Coarp uted as Shown be lou 10days, Y: 160°+3600 (n) 16003600 Cio こ125600 lence, tine totou Poond 04 fast lost on aveage is 25 6o 0 C d) Compute the vaviance of Pounds of fat t0st Per ala The γ29 Y esce equation is Y 1600 +300C9 2. 1664 xi0 yne variance of pounds op ence fat isse perday is 11464 x

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