Given:
m = 29.5 g
Cp = 0.129 J/g.oC
Ti = 26.2 oC
Tf = 94.7 oC
use:
Q = m*Cp*(Tf-Ti)
Q = 29.5*0.129*(94.7-26.2)
Q = 261 J
Answer: a
TC01E13 Calculate 9 (heat) for a system consisting of 29.5 g of gold (Cp = 0.129...
TC01E13 Calculate 9 (heat) for a system consisting of 29.5 g of gold (Cp = 0.129 J/K/g) when its temperature was raised from 26.2 °C to 94.7 °C. Select one: O a. 261 J O b. 261 kJ/mol C. 15665 J d. 1300 J e. 1300 J/mol
The specific heat of gold is 0.129 J/g°C. What is the molar heat capacity of gold? Multiple Choice Book Print O.039 J/mol"C rences 0.129 J/mol C 25.4 J/mol-"C 39.0 kJ/mol"C ( Prev 29 of 55 Next>
TC01H02 Solid calcium hydroxide weighing 1.9984 g (molar mass = 74.09 g mor') is dissolved in 100.0 mL of 1.000 mol/L HCl in an open calorimeter which has a heat capacity of 15.87 JK! The initial temperature of the Ca(OH)2 and HCl is 19.14 °C and and the temperature of the solution is 24.20 °C at the completion of the reaction. Density of 1.000 mol/L HCl = 1.015 g/mL. Heat capacity of the final solution = 3.950 JK'g? Use the...
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The molar heat capacity at constant pressure Cp,m of
certain ideal gas was found to vary according to the
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Cp,m = co + ciT, where co = 6.723 J K-1 mol-1 and cı = 0.1222 J K-2 mol-1 are constants peculiar to the gas. Calculate q, w, AU, and AH for a system comprising 3.0 mol of the gas undergoing the following reversible transformations: (a) the temperature of the gas is raised from 25.00°C to 100°C at constant pressure....
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