Silicon chloride is made up of Si & Cl. Therefore, we can write % of Si + % of Cl = 100 %
Hence, % of Si = 100 % - % of Cl = 100 % - 79.1 % = 20.9 %
Now, calculate moles of Si and Cl.
Moles of Si = % of Si / atomic mass of Si = 20.9 / 28.08 = 0.744
Moles of Cl = % of Cl / atomic mass of Cl = 79.1 / 35.45 = 2.23
Hence, ratio of moles of Si : Cl is
0.744 / 0.744 = 1 mol Si
2.23 / 0.744 = 2..997 3 mol Cl
From above values, we get empirical formula of compound as SiCl3.
Empirical formula mass of compound = 28.08 + ( 3*35.45) = 134.43 g / mol
We have relation, Molecular formula = r x empirical formula
Where r is the ratio of molar mass of substance to the empirical formula mass.
Therefore, r = 269 g / mol / 134.43 g/mol =2.00
Hence, Molecular formula of compound = 2.00 ( SiCl3. ) = Si2Cl 6
ANSWER : Empirical formula : SiCl3. Molecular formula : Si2Cl 6
2. (3 points) A chloride of silicon contains 79.1 mass % Cl. A) What is the...
A chloride of silicon contains 79.1 mass % Cl. (a) What is the empirical formula of the chloride? (b) If the molar mass is 269 g/mol, what is the molecular formula?
What would be the empirical formula for a substance that contains 84.98% by mass Hg and 15.02% by mass Cl? If the molar mass of the substance is 472.1 g/mol what is the molecular formula?
A compound contains 10.13% C and 89.87% Cl (by mass). Determine both the empirical formula and the molecular formula of the compound given that the molar mass is 237 g/mol. CCl3 C2Cl CCl
An herbicide contains only C , H , Cl , and N . The complete combustion of a 125.0 mg sample of the herbicide in excess oxygen produced 130.7 mL of CO2 and 76.26 mL of H2O vapor at STP. A separate analysis determined the 125.0 mg sample contained 34.46 mg Cl . Determine the percent composition of the herbicide. percent carbon: % percent hydrogen: % percent chlorine: % percent nitrogen: % Determine the empirical formula of the herbicide. empirical...
compound is found to contain 63.65 % nitrogen and 36.35 % oxygen by mass. the empirical formula is? the molar mass is 44.02 g/mol. what is the molecular formula? A compound is found to contain 6.360 % silicon , 36.18 % bromine , and 57.46 % iodine by mass. the empirical formula is? the molar mass is 441.7. what is the molecular formula? A compound is found to contain 64.80 % carbon , 13.62 % hydrogen , and 21.58 %...
An acid with molar mass 116.08 g/mol contains by mass, 41.4 %0, 3.47 %H, and 55.1 % Determine the molecular formula (must find empirical formula first). How many oxygens are in the molecular formula? Include the number only. Hydrogen chloride is prepared using the reaction: NaCl(aq) + H2SO4(aq) → _HCl(9) + _Na2SO4(aq) What is the limiting reagent if 4.00 g H2S04 (98.09) is reacted with 393 moles NaCl (58.44) You must balance the equation first.
need help solving these questions. Mass? 20. (3 pts) What is the empirical formula of a compound that is 58.80% C, 9.87% H, and 31.33%O by mass? 21. (3 pts) What is the empirical formula of a compound that is 71.98%C, 6.71% H, and 21.31%O by mass? 22. (2 pts) What is the molecular formula of a compound with a molar mass of 219.9 g/mol and an empirical formula of P203? 23. (2 pts) What is the molecular formula of...
uestion 23 of 34 > An herbicide contains only C, H, Cl, and N. The complete combustion of a 275.0 mg sample of the herbicide in excess oxygen produced 287.6 mL. of CO2 and 167.8 mL of H,0 vapor at STP. A separate analysis determined the 275.0 mg sample contained 75.82 mg Cl. Determine the percent composition of the herbicide. percent carbon: % percent hydrogen: % percent chlorine: % narcant nitmnen. Question 23 of 34 > percent chlorine: % percent...
What is the percent nitrogen in (NH4)₂O? Find the empirical formula of each. of the following: a) 55.37K, 14.6% P, 30.170 b.) 24.57. Na, 14.97 Si, 60.6%F C) 62.1% C, 5.217 H, 12.17N, 20.770 ) What is the molecular formula for each? a.) Empirical formula NH₂ Cl, molar mass = 51.5 g/mol 009 b.) Empirical formula Hco, molar mass=90.0g/mol c.) Empirical formula C₂H ₂ O molar mass = 88 g/mol The headache remedy ibuprofen is 75.79 8.8%H, and 15.5%0. It...
Question 3 [20 points 1. Copper sulfide is produced when copper and sulfur are heated together Use the data below, obtained after the heating process, to determine the empirical formula of this compound. Molar masses (e/mol) c S 32.06. 18 points) befor 1 Mass of crucible cover copper (B) 2 Mass of crucible + cover (g) 3 Mass of copper (B) 4 Mass of crucible cover + copper sulfide at constant weight (8)40.23 S Mass of copper sulfide (8) 6...