Question

20 pts) Consider the titration of 35.00 mL of 0.02725 M sodium - (which is the salt of p-nitrobenzoic acid) with 0.05585 M HCl. Calculate pH for the following volumes of added titrant, Vadd : Vadd = 0.00 mL Vadd = 0.70 Veg Vadd = Veg

Answer 1

plla Cuse 23-442 of paniho benzoic weld value given to you) pka + pkb 2 14-000 A ply 14-000 - 3.442 2 10.558. z kb 2 1010-558 2.7741011 . . P-nihobenzoate acts as base- Leer n O + HO - hart on 0.02725m tx tx 0-02725-x x (negled x as 16 is very less). кут Сн) Сонг) . (A) 2.77x10t 0-02725 con 2 x 2 8.69x107. & pon a pH a 2 6.061 14-000 -6.061 2 17.939) add 2 0-to veot Calculate ea Erst moles ka mules nel O-02725m x 35-00mL 2 0 -05585M X Y - Tea 2 19.08 mb. 0.70 veu a 11-950m 2 12 ml.

males no added 20-05585 x 17.95 2 0.6676 mnotes. À Inthal 20-02725x35.oome 0.095375 mmoles moles í + HCL MA 1 0.09375 0.66765 é C -0-66765 -0-66765 to 66765 E 0.2861 mmoles o 0-6676 minoles solution is buchen pH a plea + log (Base] - 23-442 + losf 0-286les mmoles fot7 Lo-66768 mmoles 13-074) Wada a eqt 17-08 ml now all p-nitrobensoate as converted to pritrobenzox and CHA). CHA) moles A monal Totat volune g. 95375 mnoles 13500 +17-08) mt 0.01831 m 2 3.61 x 10-4. Raa 103-442 HA 2 0-01831 0 0 E 0.01831

2 ca] [at] 3-6(x104 x² 0-01831-X 2) [ ao x² + 3-618104 - 0.06610 - 0 use quadran equation Solver Cit) 2 x 0:00 240 m. pH log Eat) - log Co-00240) 2 12.6207