Question

CH 203 Organic Chemistry Infrared Spectroscopy Experiment 10 points Based on the following IR and NMR spect sed on the following IR and NMR spectra and with blue molecular formula, formulate the of the compound. Identify regions of your structure that correspond to the pea graph below. Show your organic compound structure here on this page for this laboratory class. - your NMR protons are shown in faction you can tound them to a whole number by protons by a simple multiple such as a 2 or 3 ructure that correspond to the peaks that you see in the IR Acture bere on this page). No additional write-up is needed neurilen node of - nur PROBLEM 17 MW 116 *C 72.3 8H 13.9 ( C,H,O TRATTNICE TTC WWWELLERS © 1994

Answer 1

Molecular formula C7H160 So, double bond equivalent (DBE) = C +1 - H/2 7+ 1 -16/2 8-8 0 IR spectra shows a broad peak at 3400 cm-1 which indicates presence of alcoholic O- H group It also shows a stron peak at 2800-2950 cm-1 whi ch indicates presence of alkane C- H group That means it is an aliphatic alcohol It shows a 9H, triplet at 0.9 ppm and a 6H, quatret at 1.55 ppm. This shows presence of three -CH2CH3 group All these information indicates below structure OH СН160 3-ethylpentan-3-ol 1 H NMR Estimation 1.55, 6H, quatret H3C. CH2 H2 H2 C. НС СCHЗ wwww ОН 1.28, 1H br singlet 0.9 9H, triplet