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a)- 10 m: 3kg A block is released from rest at a height a and compresses a K=2m spring a distance x=20m before stopping. X=2c
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Answer #1

here,

the spring constant , K = 2 N/m

x = 2 cm = 0.02 m

using conservation of energy

initial potential energy of the block = potential energy stored in the spring

m * g * h = 0.5 * K * x^2

3 * 9.81 * h = 0.5 * 2 * 0.02^2

solving for h

h = 1.36 * 10^-5 m

the initial height of the block is 1.36 * 10^-5 m

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