Question

starting with 75.4 g NO and 15.5 H2, what is the theoretical yield of NH3 in grams? calculation based upon NO
CALCULATION based upon H2
What is the limiting reactant?
what is the theoretical yield?

Answer 1

2 NO + 5H2 → 2 NHz_ + 2 H20 mole of no Given mass of No = 75.49 = 2.51 mole Molar mass of NO . 30 g/mol mole of H₂ Giren mass of H₂ 15 5 : 7.75 mole Molar mass of it, 2 g/mol According to balanced equation; 2 mole of No react with 5 mole of H₂ Hence, val mole of No will react with 2.5 mole of Hy. → Therefore, it means 2.51 mole of No will react with (2.5 x 2051 = 6.275 mole of H₂o But 7.75 mole of H₂ is present out of which only 6.275 mole of Hy react. It means Hy is present in excesse So limiting reagent is no (which is present in less ) According to equation, 2 mole of No give 2 mole of NH3 It means 2.51 mole of no will give 2.51 mole of NH₃ Theoretic yield of NPAz = mole of NHz Molar mass of Nitz = 2:51 x 119 = 42.67 aram