Question

1. 2 NO(g)5 H2(g) >2 NHs(g) 2 H2O(g) Starting with 75.4 g NO and 15.5 g H2, what is the theoretical yield of NH3 in grams? Calculation based upon NO Calculation based upon H2 What is the limiting reactant? What is the theoretical yield?

Answer 1

on ish- The eghi I 2NO +5H₂ → 2NH₂ T 210 By stoichiometry, calculations based on nor 2 molee of No gives - 2 moles of NH₃. (OR) (2xzolg of No gives - (2x17 1g of NH3 so, 75.4 g of No 11 = 2x17x75.4 2X30 = 42.729 of NH3 - Calculation based upon Hyr 5 moles of t 2 molee of NH3 OR log of Hy giver = (2x17lg of MHz I So, 1s.sg of U₂. 11 = 2x17x Isis = 52.7 X10-' = 5:27.9 of NM I. En limiting reactant - As, 2 moles of No will react with Smolee of H₂ (OR 2x30) 9 of No will 1 1 = log of Hy so, 75.4 g of NO 1 1 4 = 16x75.4 2x373 = 12,569 of Hy But given amount of He is more ire is.sg

Limiting reactant = 1 Nol tence, theoretical yield of NH₃ will be based upon No only. So, 142.12 g of NH3 Theoretical wielt