Suppose the trooper takes t sec to catch the speeding car.
So, distance covered by the trooper in t sec -
s1 = u*t + (1/2)*a*t^2
Since, initial speed of the trooper, u = 0
So, s1 = 0 + (1/2)*3.0*t^2 = 1.5*t^2
Now, as per the given condition, the trooper starts her journey 1 sec after the speeding car passes it.
So, distance covered by the car in this time -
s2 = (t+1)*v = (t+1)*45 m
To overtake the car, we should have -
s1 = s2
=> 1.5*t^2 = (t+1)*45 m
=> 1.5t^2 - 45t -45 = 0
=> t = [45 + sqrt(45^2 + 4*1.5*45)] / (2*1.5) = [45 + 47.9] / 3.0 = 31.0 s (Answer)
Other value of t is negative so, it can be discarded.
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