Balanced chemical equation is:
Sr(OH)2 + 2 HClO4 ---> Sr(ClO4)2 + 2 H2O
Here:
M(Sr(OH)2)=0.5 M
V(Sr(OH)2)=5.33 mL
V(HClO4)=10.33 mL
According to balanced reaction:
2*number of mol of Sr(OH)2 =1*number of mol of HClO4
2*M(Sr(OH)2)*V(Sr(OH)2) =1*M(HClO4)*V(HClO4)
2*0.5*5.33 = 1*M(HClO4)*10.33
M(HClO4) = 0.516 M
Answer: 0.516 M
17 Question 17 Tries remaining Points out of 100 P Flag question If 10.33 mL of...
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Question 17 The remaining Points out of 1.00 P Flag question If 9.13 mL of the analyte HNO3 is titrated with 10.83 mL of 0.250 M Ca(OH)2, determine the molarity of the analyte solution. Units are required. Multiple attempts are allowed, however, each incorrect attempt results in a 1/5 (20%) point deduction
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Question 18 Tries remaining Points out of 100 g question How many mL of the titrant Sr(OH)2 is needed to titrate 3.09 mL of 0.75 M HCIO4, if the molarity of the titrant is 0.03? Enter in units. Multiple attempts are allowed, however, each incorrect attempt results in a 1/5 (20%) point deduction
If 9.13 mL of the analyte HNO3 is titrated with 10.83 mL of 0.250 M Ca(OH)2, determine the molarity of the analyte solution. Units are required. Multiple attempts are allowed, however, each incorrect attempt results in a 1/5 (20%) point deduction.
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How many mL of the titrant Sr(OH)2 is needed to titrate 8.84 mL of 0.75 M HCIO, if the molarity of the titrant is 0.29? Enter in units. Multiple attempts are allowed, however, each incorrect attempt results in a 1/5 (20%) point deduction
please include the work for each oart , as im trying to
practice to get a better understanding
part 1
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What is the pH of a solution of the buffer containing 0.0005 M HU5H5NUI NU UUUUU IV C5H5N? The Ką of HC5HsNt is 5.88x10-6 Multiple tries are permitted; however, 20% (1/5) point will be deducted for each incorrect response Select the correct answer to the questions below with regards to...
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