Question

17

Question 17 The remaining Points out of 1.00 P Flag question If 9.13 mL of the analyte HNO3 is titrated with 10.83 mL of 0.250 M Ca(OH)2, determine the molarity of the analyte solution. Units are required. Multiple attempts are allowed, however, each incorrect attempt results in a 1/5 (20%) point deduction

Answer 1

Balanced chemical equation is:

Ca(OH)2 + 2 HNO3 ---> Ca(NO3)2 + 2 H2O

Here:

M(Ca(OH)2)=0.25 M

V(Ca(OH)2)=10.83 mL

V(HNO3)=9.13 mL

According to balanced reaction:

2*number of mol of Ca(OH)2 =1*number of mol of HNO3

2*M(Ca(OH)2)*V(Ca(OH)2) =1*M(HNO3)*V(HNO3)

2*0.25*10.83 = 1*M(HNO3)*9.13

M(HNO3) = 0.5931 M

Answer: 0.593 M