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Part C Find the dimensions [v] of speed. Express your answer as powers of length (/), mass (m), and time t View Available Hint(s) 11에 Submitplease show work.There are three dimensions used in mechanics: length (), mass (m), and time (t). A combination of these three dimensions suffices to express any physical quantity, because when a new physical quantity is needed (e.g., velocity), it always obeys an equation that permits it to be expressed in terms of the units used for these three dimensions. One then derives a unit to measure the new physical quantity from that equation, and often its unit is given a special name. Such new dimensions are called derived dimensions and the units they are measured in are called derived units. For example, area A has derived dimensions A = 12 . (Note that dimensions of variable z is symbolized as x) You can find these dimensions by looking at the formula for the area of a square A = 82 , where s is the length of a side of the square. Clearly [a] 1, Plugging this into the equation gives [A] = [a] Part B Find the dimensions V of volume. Express your answer as powers of length (), mass (m), and time (t). View Available Hint(s) Hint 1. Equation for volume You have likely learned many formulas for the volume of various shapes in geometry. Any of these equations will give you the dimensions for volume. You can find the dimensions most easily from the volume of a cube V-e3, where e is the length of the edge of the cube.

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(B) The dimensions of volume is. [V]= lbh = (L)(L)(L) = M°°T° The dimensions of the speed are, =LT-? =M°LT

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