Question

For the following reaction, 26.5 grams of sulfur dioxide are allowed to react with 6.34 grams of water sulfur dioxide(g)+ water(l) sulfurous acid (H2SO3)(g) What is the maximum mass of sulfurous acid (H2SO3) that can be formed? grams What is the FORMULA for the limiting reagent? What mass of the excess reagent remains after the reaction is complete? grams Submit Answer Retry Entire Group 6 more group attempts remaining

Answer 1

→ H₂SO3 Sort H₂O no 26.59 noo2= suglmat = 0.ulu no = 6.349 1891mor = 0.35 tho - is limiting reagent ind H, soz NA so toned = 0.35 mol hox . I mol H₂O - 0.35 mol H₂SO3 mA,soz formed = 0.35 molx 82 g/mol = 28.9g. rso, excess = 0.414 - 0.35 = 0.064 mol mso excess = 0.064 mol x 64 g/mol = 4.099 - 4.lg.