Which of these reactions demonstrate the enthalpy of atom combination?
N(g)+3H(g)⟶NH3(g)N(g)+3H(g)⟶NH3(g)
C(graphite)+2O2(g)⟶CO2(g)C(graphite)+2O2(g)⟶CO2(g)
NO2(g)⟶N(g)+2O(g)NO2(g)⟶N(g)+2O(g)
2H2(g)+O2(g)⟶2H2O(g)2H2(g)+O2(g)⟶2H2O(g)
C(g)+O(g)⟶CO(g)
Solution:
Enthalpy of atom combination is defined as the change in enthalpy when one mole of compound is formed by the combination of its constituent atoms in gaseous state.
Hence, two reactions are showing enthalpy of atom combination,
N(g) + 3H(g) = NH3(g)
C(g) + O(g) = CO (g)
Which of these reactions demonstrate the enthalpy of atom combination? N(g)+3H(g)⟶NH3(g)N(g)+3H(g)⟶NH3(g) C(graphite)+2O2(g)⟶CO2(g)C(graphite)+2O2(g)⟶CO2(g) NO2(g)⟶N(g)+2O(g)NO2(g)⟶N(g)+2O(g) 2H2(g)+O2(g)⟶2H2O(g)2H2(g)+O2(g)⟶2H2O(g) C(g)+O(g)⟶CO(g)
Please explain
Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
From the following heats of combustion, CH3OH(l) + 3/2O2(g) → CO2(g) + 2H2O(l) ΔHorxn = –726.4 kJ/mol C(graphite) + O2(g) → CO2(g) ΔHorxn = –393.5 kJ/mol H2(g) + ½O2(g) → H2O(l) ΔHorxn = –285.8 kJ/mol Calculate the enthalpy of formation of methanol (CH3OH) from its elements. C(graphite) + 2H2(g) + ½O2(g) → CH3OH(l) Methanol (CH3OH) is an organic solvent and is also used as a fuel in some automobile engines. From...
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