Question

Two lenses are mounted in a tube such that the distance between them can be varied. This device can be used as either a telescope or a compound microscope. One lens (the objective) has a focal length of 52.5 cm.

(a) Find the focal length of the second lens (the eyepiece) such that the magnification |m|=si sN/(fobj feyepiece) of the microscope is the same as the magnification |m|=fobj/feyepiece of the telescope. Assume the distance between the two lenses of the microscope (si+feyepiece) is exactly twice as large as the distance between the two lenses of the telescope. For the near-point distance use sN=25 cm.

(b) What is the magnification achieved?

Answer 1

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a) length of telescope = fotfe Sitfe= 2(fot fel S;= 2 fot fe given SN=25cm fo=5205 cm and afsu Now Dow (2 fotfe) (25) fotte - fo assume feta 2152.5)+%. = (52.5) (52.5x) 25 105+2= 2756.25 25 x=110-25-105- x=5.25cm 11) magnification, th