Question

4. Consider the following reaction: NO (9) ► NO(g) + O(g) The concentration of NO, was monitored at a fixed temperature as a function of time during the decomposition reaction and the data is tabulated below 2nd Order Time (s) 0 INO.1 (M) 0.0100 .00887 0.00797 0.00723 0.00662 50 100 150 200 INO.1 (M) 0.00329 0.00316 0.00303 0.00292 0.00282 Time isi INO.1MI Time (s) INO.1 (M) 250 000611 5 50 0.00416 300 000567600 0.00395 350 000528 650 0.00376 400 0.00495 700 0.00359 450 0.00466 750 0.00343 Time (s) 800 850 900 950 1000 a) Using graphical analysis (using EXCEL) determine the overall reaction order. Be sure to attach a copy of the EXCEL graph with your assignment and show appropriate work! b) Determine the rate constant. c) Determine the [NO] at 2000 s (Show work!) d) Determine the t12 at t=0 s (Show work!) +2 .

I am completely lost in how to do this on excel.

Answer 1

a) The data of 1 / [NO2] versus time is plotted and a straight line is observed, this means that the reaction is of order 2.

Time [NO2] -0.255*x + 100 0 300 350 400 1[NO2] 0.01 100 0.00887 112.7395716 0.00797 125.4705144 0.00723 138.3125864 0.00662 151.0574018 0.00611 163.6661211 0.00567 176.366843 0.00528 189.3939394 0.00495 202.020202 0.00466 214.5922747 0.00416 240.3846154 0.00395 253.164557 0.00376 265.9574468 0.00359 278.551532 0.00343 291.5451895 0.00329 303.9513678 0.00316 316.4556962 0.00303 330.0330033 450 600 650 700 750 800 250 750 1000 850 900

b) The constant is:

k = m = 0.255 M-1 s-1

c) For order 2 you have the equation:

1 / [NO2] = k * t + 1 / [NO2] or

1 / [NO2] = 0.255 * 2000 + 1 / 0.01

It clears [NO2] = 0.0016 M

d) The average time is calculated:

t1 / 2 = 1 / k * [NO2] o = 1 / 0.255 * 0.01 = 392 s

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