If 168 g of an unknown liquid requires 8.75 kJ of heat to raise its temperature...

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If 168 g of an unknown liquid requires 8.75 kJ of heat to raise its temperature...

If 168 g of an unknown liquid requires 8.75 kJ of heat to raise its temperature from 26°C to 74°C, what is thespecific heat (in J/g°C) of the liquid?

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Answer 1

Answer #1

Q = mepat Q is the amount of heat required m is the mass of the substance Cp is the specific heat of the substance AT is the Q = MCAT Q = 8.75 KJ = 8.75 X 10²7 8.75X103J= (1689) Cp (74-26°C 8.75 x 103 J = (1689) (p (481% 8.7581035 1689 x 48% (p = 1.0

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Calculate the amount of heat (in kJ) required to raise the temperature of 14.0 g of...

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If 168 g of an unknown liquid requires 8.75 kJ of heat to raise its temperature...

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