Question

You tridy rieed to use Lhe appropriale technlogy to answer Lis questi researcher in a university s biology department studied the ettect ot g iculture contaminants on the stream tish population in northeastern Indiana. 5pedall designed traps co lected samples of tish at each of tour stream locations. ก็ research question was Did the diTerences in agricultural contaminants found at the four locatioris alter the proportion of the fish population by gender?" Suppose cbserved frequencies were as follows Stream Locations Male 45 40 45 35 emale 455040 48 a Focusing on the proportion of male sh at each location, tent the hypothesis that tha population proportions are equal for all four lacations UGA ה 0.05 la el of significance. State the null and alternative hypotheses : All population proportions are not qual HO: Not all population proportions are equal. ● Hn: All population proportions are not equal : ot all populalion proportiens are equal Find the value of the test statistic. (Round your answer to three decimal places.) whet is Lhe p-vlue? (Ruund your arswer to four decimal pleces.) value- what is your conclusion? Raject Ho, we cannot reject tha hypothesis that the Population proportions ara aqual in each location. Reject Ho, we conclude that the population proportions are not equal in each location. O Do not reject Ho. We carinot reject Uhe hyputhesis that the populatiun propurtion ee i each lucelio Do not reject Ho. We conclude that the population proportions are not equal in coch lccation. b)Dos it apparthat dirterences in agricultural contaminants tound at the tour locations altered tha tish population by gender? Yas, thare is evidence that diffarances in agricultural contaminants found at tha four locatinns altarea tha fish population by gender. No, thara is no evidanca that differancas in agricultural contaminants found at tha four lacations altared the fish papulation hy gandar

Answer 1

The statistical software output for this problem is:

Contingency table results:

	A	B	C	D	Total
Male	45	40	45	35	165
Female	45	50	40	48	183
Total	90	90	85	83	348

Chi-Square test:

Statistic	DF	Value	P-value
Chi-square	3	2.517073	0.4722

Hence,

a) Hypotheses: Option D is correct.

Test statistic = 2.517

p - Value = 0.4722

Conclusion: Option C is correct.

b) Option B is correct.