Question

Lab Exercise 4B Example: Calculation of C, for Tube #2 ? Concentration of maltese solution (C) 2.5mg/ml. Volume of standard solution (V.) - 200 ml 0.2 ml Concentration of maltose solution after dilution (C) Volume of maltose solution after dilution (V.) = 100 ml -0.05 mg/ml C 2.5 mg/ml X 0.2 100 ml Absorbund at 540 Tube 0.0 b. 554 HE Volume of Volume of water concentration added to make standard maltose of maltose number solution (L) upto 1000 L (mg/ml) I lOlomL) 1000 ML 200 800 0.05 3 Homb-46) Coono. . 9 0.721 4 1600ML GULEloon on 0.3 1.167 5 800110810 200 140 2140-411122 6 Pool | ML0.2LONL) 0.5 11.3393 1 11. Graph the absorbance vs. mg/ml of maltose using TAILS on the graph paper (page 157) Final absorbance V A. Draw a 'line of best fit' through your data points B. You now have a reference graph, or Standard Curve, to estimate the amount of maltose produced by your amylase enzyme in Parts I and III 1. use the recorded absorbance @ 540 nm 2. find that absorbance value on the Y axis of standard curve 3. look for the mg/ml of maltose on the X axis Maltose (mg/ml)
plote a graph

Answer 1

540 nm) adsorbance (at 0:5 o .05 .1 0.2 0.3 ory 0.5 0.5 (2 maltose (mg/me)