Question

3. Solubility and equilibrium Explain the following changes in equilibrium observed in experiments The explanation must considera compounds and all of major factors. 15 pts) CHCI . CHON CH, OCH NI in water nearly 100% viold in hexane nearly 0% yield 4. Basicity and equilibrium) Complete the following reactions you must show more than one possible mechanisms before you choose the better one with a greatly detailed explanation. Then, explain the equilibrium and the explanation must be done in terms of basicity of each compound. 6 pts 1, 0, + CH4,009

Answer 1

3. CH_{​​​​​3} Cl + CH_{​​​​​3} ONa = CH_{​​​​​3} O CH_{​​​​​3} + NaCl

In the above reaction, In aqueous medium, the reaction proceeds and gives the products.

But in hexane it doesn't.

First of all, we have to see the interaction of solvent in this case. As water is a polar protic solvent , it solvates and creates the ion for reaction.

CH_{​​​​​3}​​​​ONa = CH_{​​​​​3} O^​​​- + Na⁺

CH_{​​​​​3} Cl = CH_{​​​​​3}^​+ + Cl^{​​​​​-}

But, Hexane is non polar solvent, it cannot initialize the reaction.