Question

Enter your answer in the provided box. In the Mond process for the purification of nickel, carbon monoxide is reacted with heated nickel to produce Ni(CO), which is a gas and can therefore be separated from solid impurities: Ni(s) + 4C0g)#Ni(CO),g) Given that the standard free energies of formation of CO(g) and Ni(CO),(g) are -137.3 and -587.4 kJ/mol, respectively, calculate the equilibrium constant of the reaction at 56.0°C. Assume that AG is temperature-independent.

Answer 1

0 Given Given the neaction - Ni (s) + 4 CO (2) = Ni(CO), () We know that - 1992n = En aqj (product) – En aqj (maactombs) So, for the reaction - 4= [1 x 44 [ico,}] – [ox=%(6)} + {ax aç; (co}] Given - AGg Of co(q) == 137.3 KJ/mos AGF o Ni(s) = 0 kJ/mol AG; Of NICCO )4 (8) = -587.4 kJ/mol

Accondingly, action = 30 x 45 Ens(c0n7}] - [ux 4G; (v) } + {9x 48; (c)}] =[ix [587:4)] - [{1x0}+{4x (-137,3)}] = -587.4 - [0 + (-549.2)] = -587.4 - [-549.2] = - 587. 4 + 549.2 = 38.2 kJ/mol

Also we know that - at equilibrium, AGO = -RT Ink Whene, R= universal gar constant T= temperature K = equilibrium constant

Given T= 56.0°C = (56+273) K = 329 K R= 8.314 J. mof-!. K-I (known) AGA n = 38.2 KJ/mol = (38.2 X1000) I/mol = 38200 J. mol- K = ?

Accordingly, AG = ~ RT Ink or, - RT IN K = 4Giron or, In K = - 4 Grey RX T or, in K = - 38 200 Ji mot- 8.314 7. most! KX x 329 X or, In K = -13.965 or, K = 7-13.965 or, K = 8.61 x 10-7 i. The value of k is 8.61 x 10-7. Ans.