TOGO Estimate the H-F bond enthalpy knowing that the Heat of Formation of hydrogen fluoride (AH;,...

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Answer 1

Answer #1

The reaction is

H₂ + F₂ $\rightarrow$ 2 HF (1)

From reaction 1.

Heat of formation of 2× HF = $\sum$ Bond enthalpy of reactants - $\sum$ Bond enthalpy of products

Or, -271× 2 = (436+157) - 2× Bond enthalpy of HF

Or, 2× Bond enthalpy of HF = - 271×2 - (436 +157)

or, 2× Bond enthalpy of HF = - 1135.3 KJ

Or, Bond enthalpy of HF = (1135 /2) = 567.5 KJ/mole.

Answer 2

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