Question

Water is flowing in the pipe shown in the figure below, with the 7.75-cm diameter at point 1 tapering to 3.75 cm at point 2, located y 13.5 cm below point 1. The water pressure at point 1 is 3.20 x 104 Pa and decreases by 50% at point 2. Assume steady, ideal flow. What is the speed of the water at the following points? (a) point 1 m/s (b) point 2 m/s Need Help? Read It

Answer 1

Pornt a de = 3.751 Point 1 di = 7.75cm 27.75x10m di +0.0775m de=0.0.375 m = 9, =om Сурчn ) h = Y,= 13.5cm 9, = 0.135 m Pr = 3.20 x204A P2 = 150% offi = 1 x 3.200104 Pa. Py = 16X104 Pa YE? Y = ? s from equation of continuity A Area As Tid? AW, = A. Va di v, - di 12 [Ng = 4.714, 1–0 ► from equations of Beancalid's - Pit figh, t & puit = P2 +59h 2 + 1 2 882 - f= 1000 byl m? - for water Pit ggg, + at a pay = P₂ + 1 - 2 1 1 2 -

Scubstiteste Dina Pu+ + (4.971 v) Pit egy, - P2 = 12 g (4.271 8,3 - 1 2 vi - espri (42719-17) = $$ v/17.241) Pirtsgy, - Pq = (8.62)$4 vita Pet fgy, - P2 8.62 x 8 Sobaxg 63.204001) +(1000X9.8140.135) -(1.6 moty 6.62 x 1000 V = 1.4176 z 1,49 mls) - at poine) 0 >> Vo = 4.27) XV, = 4.871x7.42 No = 6.06 mis l at point