5.39*10^-5 M means 1 liter (1000 ml) solution contains 5.39*10^-5 moles of solute.
Let X g/mol is the molar mass of solute. Then,
Mass of solute = moles * molar mass = (5.39*10^-5)*X grams
= 5.39*10^-5 * X * 1000 miligrams = (5.39*10^-2)X mg
Now,
Concentration in mg/ml = (5.39*10^-2)*X / 1000 = (5.39*10^-5)*X mg/ml .....Answer
Let me know if any doubts.
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