if 300. mL of 1.50 M Mg(nNO3)2 produces 400. mL of AgNO3, what is the concentration...

Question

Question

if 300. mL of 1.50 M Mg(nNO3)2 produces 400. mL of AgNO3, what is the concentration in M?

Answer 1

Answer #1

Applying molarity equation $M_{1}V_{1} = M_{2}V_{2}$

M₁ = 1.50M , V₁ = 300 ml

M₂= ? ,V₂ =400 ml

$1.50\times 300 = M_{2}\times400$

$M_{2}= 450/400 = 1.125 M$

Answer 2

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